3.144.252.201
Get online IP address. What is my IP provide both IPV4 and IPV6 Address. There are lot of ways to get the client IP address using PHP, Java, Asp.net
function client_ip() {
$ipaddress = '';
if (isset($_SERVER['HTTP_CLIENT_IP']))
$ipaddress = $_SERVER['HTTP_CLIENT_IP'];
else if(isset($_SERVER['HTTP_X_FORWARDED_FOR']))
$ipaddress = $_SERVER['HTTP_X_FORWARDED_FOR'];
else if(isset($_SERVER['HTTP_X_FORWARDED']))
$ipaddress = $_SERVER['HTTP_X_FORWARDED'];
else if(isset($_SERVER['HTTP_FORWARDED_FOR']))
$ipaddress = $_SERVER['HTTP_FORWARDED_FOR'];
else if(isset($_SERVER['HTTP_FORWARDED']))
$ipaddress = $_SERVER['HTTP_FORWARDED'];
else if(isset($_SERVER['REMOTE_ADDR']))
$ipaddress = $_SERVER['REMOTE_ADDR'];
else
$ipaddress = 'UNKNOWN';
return $ipaddress;
}
public string client_ip()
{
System.Web.HttpContext context = System.Web.HttpContext.Current;
string ipAddress = context.Request.ServerVariables["HTTP_X_FORWARDED_FOR"];
if (!string.IsNullOrEmpty(ipAddress))
{
string[] addresses = ipAddress.Split(',');
if (addresses.Length != 0)
{
return addresses[0];
}
}
return context.Request.ServerVariables["REMOTE_ADDR"];
}
import java.net.DatagramSocket;
import java.net.InetAddress;
try(final DatagramSocket socket = new DatagramSocket()){
socket.connect(InetAddress.getByName("8.8.8.8"), 10002);
ip = socket.getLocalAddress().getHostAddress();
}
another example
import java.net.InetAddress;
import java.net.UnknownHostException;
public class client_ip {
public static void main(String[] args) {
InetAddress ip;
String hostname;
try {
ip = InetAddress.getLocalHost();
hostname = ip.getHostName();
System.out.println("Your current IP address : " + ip);
System.out.println("Your current Hostname : " + hostname);
} catch (UnknownHostException e) {
e.printStackTrace();
}
}
}
We can not get the client IP address using JavaScript. We can build an API and get the IP address using server side languages like PHP/Java.